LTC6104 TYPICAL PERFORMANCE CHARACTERISTICSStep Response Falling EdgeStep Response Falling EdgePSRR vs Frequency 160 – V – V S + 50mV VSENSE SENSE ∆V – SENSE = 100mV VS – 50mV 140 7V V+ = 4V IOUT = 0µA VOUT 120 6V 5.5V V+ = 12V I 100 OUT = –100µA 4.5V 80 PSRR (dB) T T 60 A = 25°C A = 25°C RIN = 100Ω V V S = 12V S = 12V ROUT = 5k R R IN = 100Ω IN = 100Ω 40 C V 2V OUT = 5pF R OUT R OUT = 5k OUT = 5k GAIN = 50 1V V + = V V + SENSE S SENSE = VS 20 IOUTDC = 100µA 0.5V V V REF = 6V REF = 4.5V VINAC = 50mVP-P 0 TIME (1 TIME (1 µs/DIV) µs/DIV) 0.1 1 10 100 1k 10k 100k 1M 6104 G20 6104 G19 FREQUENCY (Hz) 6104 G20 PIN FUNCTIONS OUT (Pin 1): Current Output. OUT will source or sink a A resistor (RIN) tied from one end of RSENSE to –INB sets current that is proportional to the sense voltage into an the output current IOUT = VSENSE/RIN. VSENSE is the voltage external resistor. A voltage reference is required to provide developed across the external RSENSE (Figure 1). the proper positive offset voltage so that the output can –INA (Pin 7): The negative input of the internal sense swing both positive and negative. amplifi er A. The internal sense amplifi er will drive –INA V– (Pin 4): Negative Supply (or Ground for Single-Supply to the same potential as +INA when VSENSE is positive. A Operation). resistor (RIN) tied from one end of RSENSE to –INA sets the output current I +INB/V OUT = VSENSE/RIN. S (Pin 5): The positive input of the internal sense amplifi er B. It also works as the positive supply input. +INA (Pin 8): The positive input of the internal sense Supply current is drawn through this pin. amplifi er A. –INB (Pin 6): The negative input of the internal sense amplifi er B. The internal sense amplifi er will drive –INB to the same potential as +INB when VSENSE is negative. 6104f 6