Datasheet AD8010 (Analog Devices) - 7

ManufacturerAnalog Devices
DescriptionLow Power, High Current Distribution Amplifier
Pages / Page12 / 7 — AD8010. 0.2. G = +1. L = 18.75. 0.15. O = 0.2V p-p. O = 4V p-p. 0.1. …
RevisionB
File Format / SizePDF / 192 Kb
Document LanguageEnglish

AD8010. 0.2. G = +1. L = 18.75. 0.15. O = 0.2V p-p. O = 4V p-p. 0.1. 0.05. VOLTS. –0.05. –0.1. –0.15. –0.2. 50mV. 20ns. G = +2, –1. VO = 4V p-p. 100. 1000

AD8010 0.2 G = +1 L = 18.75 0.15 O = 0.2V p-p O = 4V p-p 0.1 0.05 VOLTS –0.05 –0.1 –0.15 –0.2 50mV 20ns G = +2, –1 VO = 4V p-p 100 1000

Model Line for this Datasheet

Text Version of Document

AD8010 5 0.2 G = +1 G = +1 4 R R L = 18.75 L = 18.75 0.15 V 3 V O = 0.2V p-p O = 4V p-p 0.1 2 0.05 1 0 0 VOLTS VOLTS –0.05 –1 –0.1 –2 –0.15 –3 –0.2 –4 50mV 20ns 1V 20ns –5
Figure 21. Small-Signal Pulse Response; G = +1 Figure 24. Large-Signal Pulse Response; G = +1
G = +2, –1 0.2 G = +2, –1 4 R R L = 18.75 L = 18.75 0.15 V 3 VO = 4V p-p O = 0.2V p-p 0.1 2 0.05 1 0 0 VOLTS VOLTS –0.05 –1 –0.1 –2 –0.15 –3 –0.2 –4 50mV 20ns 1V 20ns
Figure 22. Small-Signal Pulse Response; G = +2, –1 Figure 25. Large-Signal Pulse Response; G = +2, –1
100 1000 nV/ Hz – pA/ Hz 100 INVERTING CURRENT 10 10 NONINVERTING CURRENT INPUT VOLTAGE NOISE INPUT CURRENT NOISE 1 1 10 100 1k 10k 100k 1M 10M 10 100 1k 10k 100k 1M 10M FREQUENCY – Hz FREQUENCY – Hz
Figure 23. Input Voltage Noise vs. Frequency Figure 26. Input Current Noise vs. Frequency REV. B –7–