.. effective the voltage drop across the source resistor must be comparable to the threshold, making it a large fraction of a volt. The consequence is that the equalizing resistors dissipate large power, and the voltage drop across them eats ...
.. clockwise. On Range C, an external voltage source that connects to R 13 controls the load current at a rate of 1 A per volt with P 1 set fully clockwise. You can drive the external input with a function generator to test a power ...
.. of 63 V means that the required caps are both big and expensive. A second approach would be to increase the LT8362 output a volt or two and add an LDO regulator to the output. This requires a high voltage LDO regulator, which usually costs ...
.. positive output are shown in Figure 2. Figure 2. The topology of a 2-quadrant operation with a positive output. When the volt-second balance is in a steady state, the duty cycle can be derived from the expression: To verify the design, ...
.. to (I DS )×(R1). Op-amp U1B inverts this voltage and buffers it out for plotting, scaled at either 1 mA or 10 mA per volt. Figure 1. The curve tracer circuit is a simple transimpedance amplifier that converts the device test's I DS ...
.. sinking current at its cathode and turning on the LED through D2. The potential at the TL431 cathode will drop as low as a volt or two. The TL431 can sink upwards of 100 mA and lights the LED very well. The TL431 will turn on when the sensed ...
.. Figure 1. Dual-output hybrid SEPIC-Ćuk converter. To find out the output voltages we apply the principle of inductor volt-second balance and capacitor charge balance. To simplify the calculus, we neglect the voltage drop over the ...
.. coil if available or a suitable coil from some other device. The coil in the prototype was salvaged from a surplus 24 volt relay. Actually, two relays were needed since the first was destroyed in the attempt to remove the surrounding ...
.. voltage across the two 1 ohm emitter resistors to a precise value set by the selected 220 ohm across the inputs. With a 15 volt supply, one can calculate that there's about 16 mV across the 220 ohm in the schematic and the op-amps force ...
.. resistance needs to be high enough to not exceed the power supply current limit. I wanted to stay below 0.5 amp with a 5 volt supply (5 / 0.5 = 10 ohms) and targeted 10 to 15 ohm coil. Figure 2. Electromagnetic coil. As the circuit has now ...