.. first glance. However, any fraction of a millivolt of the input-voltage offset times a gain of 1000 yields a fraction of a volt at the output. When you calculate the differences of the 10.02-mV and 0 V output voltages for the respective ...
.. current only during its on time, and an internal resistive-voltage drop exists in the secondary output. Therefore, the volt-time product of the main transformer's secondary output is not exactly zero, which is a required condition ...
Introduction A 500 V protection circuit for low voltage high impedance measuring instruments is shown in Figure 1. The protection is accomplished by limiting the amount of current going into the measuring instrument. The circuit will protect ...
.. however, IC1’s “-” pin will be near ground when the voltage across R1 is less than 1.24 V, and about a volt below V+ when the voltage across R1 is greater than 1.24 V. Figure 1. This low-cost, space-saving circuit will ...
.. imposes a self-discharge current of less than 1 mA, which represents a capacitor-battery discharge rate of 5000 sec per volt into an open circuit. You can reduce the LP2996's self-discharge current by applying an external control ...
.. resets through R 3 and D 3 . The voltage at T 1 ’s secondary winding goes slightly negative to balance the core's volt-second characteristic, which forward-biases Q 3 ’s body diode without current, and Q 4 ’s body diode ...
.. but it unconditionally starts at a very low voltage. Previous silicon-transistor boost circuits required approximately a volt to start and many more components. Figure 1. This open-loop boost circuit starts with as little as 260-mV input ...
.. shown in Figure 1 enables an amplifier that can deliver higher output voltage swings while still using standard (e.g., 15-volt) op amps at the front end. Figure 1. Schematic of high output voltage swing current booster. Higher swing is ...
.. near the center of its 0 to 2.5 V range provides the best linearity. Figure 1. Clamp circuit to precision clamp a 2.5 Volt output while operating on a 2.5 Volt power supply. To achieve this, the reference voltage is halved via the ...
.. C FLY , a second inductor L2, a catch diode D4, and the negative output capacitor C O2 . According to the inductor volt-second balance for the circuit loop of C O1 -L1-C FLY -L2, the average voltage across L1 and L2 is zero, so the ...